A man crosses the river perpendicular to river in time t seconds and travels an equal distance down the stream in T seconds. The ratio of man's speed in still water to the river water will be:

Options

A. `(t^(2)-T^(2))/(t^(2)+T^(2))`
B. `(T^(2)-t^(2))/(T^(2)+t^(2))`
C. `(t^(2)+T^(2))/(t^(2)-T^(@))`
D. `(T^(2)-T^(2))/(T^(2)-t^(2))`.

Answer

C