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The position vector of a particle moving...

The position vector of a particle moving in x-y plane is given by `vec(r)=(t^(2)-4)hat(i)+(t-4)hat(j)`. Find
(a) Equation of trajectory of the particle
(b)Time when it crosses x-axis and y-axis

Text Solution

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(A) `y^(2)+8y+12=x,` (b0 crosses x axis when t=4 sec, crosses y axis when=`+-2sec.`
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Knowledge Check

  • The position vector of a particle moving in x-y plane is given by vec(r) = (A sinomegat)hat(i) + (A cosomegat)hat(j) then motion of the particle is :

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    `SHM`
    B
    on a circle
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    D
    with constant acceleration

  • The position of a particle at time moving in x-y plane is given by vec(r) = hat(i) + 2 hat(j) cos omegat . Then, the motikon of the paricle is :

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  • The position of a particle at time moving in x-y plane is given by vec(r) = hat(i) + 2 hat(j) cos omegat . Then, the motikon of the paricle is :

    A
    open a straight line
    B
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    periodic
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