`inte^(-v/u)dv`

Find the value of int_(u)^(v)Mvdv

Evaluate the integral int_(u)^(v)Mvdv

int(u(v(du)/(dx)-u(dv)/(dx)))/(v^(3))dx=

If u and v are two functions of x then prove that : int uv dx = u int v dx - int [ (du)/(dx) int v dx ] dx Hence, evaluate int x e^(x) dx

int(vdu-udv)/(u^(2)+v^(2))=

int(1)/sqrt(1-2v^(2))dv

Evaluate the following : int_(u)^(v) " mv dv"

If sqrt(u/v)+sqrt(v/u) =6 , then (du)/(dv) =

If e^(v)+e^(u)=e^(v+u) , then (du)/(dv)=

If sqrt((v)/(u))+sqrt((u)/(v))=6, then (dv)/(du)=