33/(x-5)(x-6)=(25)/((24)^(2))

Solve : (x-5)(x-6)=25/((24)^2)

Solve: x+(1)/(x)=25(1)/(25)(x-3)(x-4)=(34)/((33)^(2))

5^(x)-24=(25)/(5^(x))

(x^(24))/(x^(25))

(x+5)/(2)+(x-5)/(3)=(25)/(6)

The coefficient of x^(324) in the expansion of (x+1)(x2)^(2)(x+3)^(3)(x4)^(4)......(x24)^(24)(x+25)^(25) is

If A={1,2,3},B={3,4}and C={4,5,6}, "then prove that" (AxxB)uu(AxxC) ={(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5 ),(2,6),(3,3),(3,4),(3,5),(3,6)}

If A={1,2,3},B={3,4}and C={4,5,6}, "then prove that" (AxxB)uu(AxxC) ={(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5 ),(2,6),(3,3),(3,4),(3,5),(3,6)}