If `cos alpha+cos beta=3/2 and sin alpha+sin beta=1/2 and theta` is the arithmetic mean of `alpha and beta,` then `sin 2theta+cos 2theta` is equal to :

If cos alpha + cos beta = 3/2 and sin alpha + sin beta = 1/2 and theta is the arithmetic mean of alpha and beta then sin 2 theta + cos 2 theta

If cos alpha+cos beta=(3)/(2) and sin alpha+sin beta=(1)/(2) and theta is the arithmetic mean of alpha and beta, then sin2 theta+cos2 theta is equal to

If cos alpha + cos beta = a, sin alpha + sin beta = b and theta is the arithmetic mean between alpha and beta then sin 2 theta + cos 2 theta is equal to

If cos alpha + cosbeta=a, sinalpha + sinbeta=b and theta is the arithmetic mean between alpha and beta , then (sin2theta + cos 2theta) is equal to :

If cos alpha + cosbeta=a, sinalpha + sinbeta=b and theta is the arithmetic mean between alpha and beta , then (sin2theta + cos 2theta) is equal to :

If cos alpha+ cos beta= a, sin alpha+ sin beta= b and alpha- beta= 2 theta . Then (cos 3 theta)/(cos theta)=

If cos alpha+cos beta=a*sin alpha+sin beta=b and alpha-beta=2 theta then (cos3 theta)/(cos theta)=