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[" Prove the identities i "],[(log_(a)n)/(log_(ab)n)=1+log_(a)b]

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Prove the following identities: (a) (log_(a) n)/(log_(ab) n) = 1+ log_(a) b" "(b) log_(ab) x = (log_(a) x log_(b) x)/(log_(a) x + log_(b) x) .

Prove the following identities: (a) (log_(a) n)/(log_(ab) n) = 1+ log_(a) b" "(b) log_(ab) x = (log_(a) x log_(b) x)/(log_(a) x + log_(b) x) .

Prove the following identities: (a) (log_(a) n)/(log_(ab) n) = 1+ log_(a) b" "(b) log_(ab) x = (log_(a) x log_(b) x)/(log_(a) x + log_(b) x) .

Prove the following identities: (a) (log_(a) n)/(log_(ab) n) = 1+ log_(a) b" "(b) log_(ab) x = (log_(a) x log_(b) x)/(log_(a) x + log_(b) x) .

Prove that : (viii) (log_(a)x)/(log_(ab)x) = 1+log_(a)b .

Prove that ((log)_(a)N)/((log)_(ab)N)=1+(log)_(a)b

Prove the identity; (log)_(a)N log_(b)N+(log)_(b)N log_(c)N+(log)_(c)N log_(a)N=((log)_(a)N log_(b)N log_(c)N)/((log)_(abc)N)

Prove that: (log_a(log_ba))/(log_b(log_ab))=-log_ab

Prove that ((log)_a N)/((log)_(a b)N)=1+(log)_a b

Prove that ((log)_a N)/((log)_(a b)N)=1+(log)_a b