x^(2)y^(2)=(x-y)^(4)

(x-y)(x+y)(x^(2)+y^(2))(x^(4)+y^(4)) is equal ot: x^(16)-y^(16)(b)x^(8)-y^(8)x^(8)+y^(8)(d)x^(16)+y^(16)

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2), respectively.If vertex and focus both lie in the first quadrant, then the equation of the parabola is (x+y)^(2)=(x-y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=8(x+y-2)

Simplify: (x^(2)-2y^(2))(x+4y)x^(2)y^(2)

The number of pairs (x,y) which will satisfy the equation x^(2)-xy+y^(2)=4(x+y-4) is

The equation of the tangent of the circle x^(2)+y^(2)+4x-4y+4=0 which make equal intercepts on the positive coordinate axes,is -x+y=2x+y=2sqrt(2)x+y=4x+y=8

The circle x^(2)+y^(2)+4x-4y-4=0 touches

Add : x^(2) y^(2) , 2x^(2)y^(2) , - 4x^(2)y^(2) , 6x^(2)y^(2)

Statement 1: The equations of the straight lines joining the origin to the points of intersection of x^(2)+y^(2)-4x-2y=4 and x^(2)+y^(2)-2x-4y-4=0 is x-y=0 . Statement 2: y+x=0 is the common chord of x^(2)+y^(2)-4x-2y=4 and x^(2)+y^(2)-2x-4y-4=0