Velocityof a particle as function of displacement `x` is given by `v=bx^(1//2)`. Then the displacement as function of time is:

The force on a particle as the function of displacement x is given by F = 9 + 0. 3x . The work done corresponding to displacement of particle from x = 0 to x = 2 unit is

A particle moves with an initial velocity v_(0) and retardation alphav, where alpha is a constant and v is the velocity at any time t. If the particle is at the origin at t=0 , find (a) (i) velocity as a function of time t. (ii) After how much time the particle stops? (iii) After how much time velocity decreases by 50% ? (b) (i) Velocity as a function of displacement s. (ii) The maximum distance covered by the particle. (c ) Displacement as a function of time t.

A point moves such that its displacement as a function of time is given by x^3 = r^3 + 1 . Its acceleration as a function of time t will be

A point moves such that its displacement as a function of time is given by x^3 = t^3 + 1 . Its acceleration as a function of time t will be

The rate of change of displacement with respect to time is known as velocity.If displacement of a particle is s=3t^(2)+4t+5 then velocity as a function of time

The velocity of a particle executing SHM is V_1 when displacement is X_1 and V_2 when displacement is x_2 . What is the amplitude of vibration of the particle?

Write the expression of potential energy of SHM particle (i) as a function of displacement (ii) as a function of time.

[" Velocity of a particle moving along "x" -axis "],[" as a function of time is given as "v=(4-],[t^(2))m/s," where "t" is time in second.The "],[" displacement of particle during "t=0s" to "t],[=1s" is "]

If velocity of a particle is v=bs^(2) ,where b is constant and s is displacement. The acceleration of the particle as function of s is?