`[(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))-(sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2))]` सरल करें:

Options

A. `2sqrt(6)`
B. `4sqrt(6)`
C. `2sqrt(3)`
D. `3sqrt(2)`

Answer

B

Explanation

`[(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))-(sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2))]`
`implies (sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))xx(sqrt(3)+sqrt(2))/(sqrt(3)+sqrt(2))-`
`(sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2))xx(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))`
`implies ((sqrt(3)+sqrt(2))^(2))/(3-2)-((sqrt(3)-sqrt(2))^(2))/(3-2)`
`implies 4sqrt(6)`