`2C_0+2^2/2 C_1+2^3/3 C_2+.............+2^11/11 C_10 =?`

Evaluate : 2C_0+(2^2C_1)/2+(2^3C_2)/3+........+(2^11C_10)/11 .

Given that 1/(r+1)""^nC_r=1/(n+1)"'^(n+1)C_(r+1) Prove that 2""^10C_0+2^2/2""^10C_1+2^3/3""^10C_2+.....+2^11/11""^10C_10=(3^11-1)/11

2.C_0 + (2^2)/(2).C_1 + (2^3)/(3).C_2 + ……+(2^11)/(11).C_10 =

Find the sum 2C_0+(2^2)/2C_1+(2^3)/3C_2+(2^4)/4C_3+........+(2^(11))/(11)C_(10)dot

If C_r stands for ^10C_r show that 2.C_0+2^2/2.C_1+2^3/3.C_2+…+2^11/11.C_10= (3^11-1)/11)

Find the sum 2C_0+(2^3)/2C_1+(2^3)/3C_2+(2^4)/4C_3++(2^(11))/(11)C_(10)dot

If "^(10)C_(0)+^(11)C_(1)+^(12)C_(2)+.........^(100)C_(90)=^(x)C_(y) then (x-y)/(11) is

Prove that 5.C_(0) +5^(2).(C_(1))/(2) +5^(3).(C_(2))/(3)+…+5^(n+1).(C_(n))/(n+1)=(6^(n+1)-1)/(n+1) Hence show that 5.C_(0) +(5^(2))/(2).C_(1)+(5^(3))/(3).C_(2)+….+(5^(11))/(11).C_(10)=(6^(11)-1)/(11)

Find the sum 2C_(0)(23)/(2)quad C_(1)+(2^(3))/(3)C_(2)+(2^(4))/(4)C_(3)+...+(2^(11))/(11)C_(10)