In Figure, `P Q=P R` . Show that `P S > P Q` Figure

In Figure, P Q=P Rdot Show that P S > P Q

In Figure, /_P Q R=\ /_P R Q , then prove that /_P Q S=\ /_P R Tdot

In Figure, A P _|_l a n d P R > P Q . Show that A R > A Q Given: A P_|_l a n d P R > P Q To Prove: A R > A Q Construction: Mark a point S on P R such that P S=P Qdot Join A S

In Figure, P Q > P R. Q S\ a n d\ R S are the bisectors of /_ Q and /_R respectively. Prove that S Q > S R .

In Figure, P S=P R ,\ \ /_T P S=\ /_Q P Rdot Prove that P T=P Q

In Figure, O P||R S . Determine /_P Q R

In Figure, A P || B Q\ || C R . Prove that a r\ ( A Q C)=\ a r\ (P B R)

In Figure, A P\ _|_l\ a n d\ P R > P Q . Show that A R > A Q .

In Fig. 4.90, if P S Q R , prove that P O S ~ R O Q . (FIGURE)

In Figure, P Q R S is a quadrilateral in which diagonals P R and Q S intersect in O . Show that P Q+Q R+R S+S P > P R+Q S PQ+QR+RS+SP<2 (PR+QS) Figure