" let "p_(n)" denotes product of binomial coefficients in "(1+x)^(n)" then "(P_(n+1))/(P_(n))=

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 8!P_(n+1)=9^(8)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If n be a positive interger and p_(n) denotes the product of the binomial coefficients in the expansion of (1+x)^(n)," Prove that, "(P_(n+1))/(P_(n))=(n+1)^(n)/(n!) .

If n be a positive integer and P_(n) denotes the product of the binomial coefficients in the expansion of (1+x)^(n), prove that (P_(n+1))/(P_(n))=((n+1)^(n))/(n!)

If n be a positive integer and P_n denotes the product of the binomial coefficients in the expansion of (1 +x)^n , prove that (P_(n+1))/P_n=(n+1)^n/(n!) .

If P_n denotes the product of all the coefficients of (1+ x)^n and 8! P_(n+1)=9^8 P_n then n is equal to