m^(2)-3m-10=0

(2m^(2)-3m+10)-:(m-5)

Let the line 3x+4y=m touches the circle x^(2)+y^(2)-10x=0 .If the possible values of m are m_(1) and m_(2) then ((m_(1)+m_(2)))/(10) is

A normal to the parabola y^(2)=4ax with slope m touches the rectangular hyperbola x^(2)-y^(2)=a^(2) if 1) m^(6)+4m^(4)-3m^(2)+1=0 2) m^(6)-4m^(4)+3m^(2)-1=0 3) m^(6)-4m^(4)-3m^(2)+1=0 4) none

The roots of the quadratic equation m^2-3m+1=0 are

The roots of the quadratic equation m^2-3m+1=0 are

The roots of the quadratic equation m^2-3m+1=0 are

Simplify the following: 10m^(2) - 9m + 7m - 3m^(2) - 5m -8