(cos theta+i sin theta)^(n)=

((cos theta+i sin theta)^(4))/((sin theta+i cos theta)^(5)) is equal to.

((cos theta-i sin theta)^(4))/((sin theta+i cos theta)^(5)) is equal to

((cos theta+i sin theta)^(4))/(((sin theta+i cos theta))^(5)) is equal to

"(cos theta+i sin theta)^(6)(cos theta-i sin theta)^(-3)

(1+cos theta+i sin theta)^(10)+(1+cos theta-i sin theta)^(10)=

If (cos theta + i sin theta)(cos 2 theta +i sin 2 theta ) …(cos n theta + i sin n theta)=1 then the value of theta is (m are integers)-

The number of values of theta in (0, pi] , such that (cos theta + i sin theta) (cos 3 theta + i sin 3 theta) (cos 5 theta + i sin 5 theta) (cos 7 theta + i sin 7 theta) (cos 9 theta + i sin 9 theta) = -1 is

The general value of theta which satisfies the equation (cos theta + i sin theta) (cos 3 theta + I sin 3 theta) ….. {cos(2n - 1) theta + I sin (2n - 1) theta} = 1 is