4x-7y+28=0,5y-7x+9=0

Solve the following by using cross multiplication method 4x - 7y + 28 = 0 , 5y - 7 x + 9 = 0

Solve fir x and y: [5x-4y+8=0],[7x+6y-9=0]

Find value of x and y: (5x-4y+8=0),(7x+6y-9=0)

Find value of x and y: (5x-4y+8=0),(7x+6y-9=0)

Find the orthocentre of the triangle formed by 4x-7y+10=0, x+y-5=0, 7x+4y-15=0 .

The orthocentre of the triangle whose sides are given by 4x-7y+10=0,x+y-5=0 and 7x+4y-15=0

Find radical centre of three circles discribed on the three sides 4x-7y+10=0, x+y-5=0 and 7x+4y-15=0 of triangle as diameters .

The area of the quadrilateral formed by thelines 4x-7y-13=0, 8x-y-39=0, 4x-7y+39=0, 8x-y+13=0 is

The orthocentre of the triangle formed by the lines x-7y+6=0,2x-5y-6=0 and 7x+y-8=0 is

Solve, using cross - multiplication : 4x - 7y + 28 = 0 and -7x + 5y + 9 = 0 .