[(2)/(3x+2y)+(3)/(3x-2y)=(17)/(5)],[(5)/(3x+2y)+(1)/(3x-2y)=2]

Solve the following system of equations: (2)/(3x+2y)+(3)/(3x-2y)=(17)/(5),quad (5)/(3x+2y)+(1)/(3x-2y)=2

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5,5/(3x+2y)+1/(3x+2y)=6/5

Solve : {:((34)/(3x+4y)+(15)/(3x-2y)=5),((25)/(3x-2y)-(8.50)/(3x+4y)=4.5):}

{:((1)/(2(x + 2y)) + (5)/(3(3x - 2y))=(-3)/(2)),((5)/(4(x + 2y)) - (3)/(5(3x - 2y)) = (61)/(60)):}

Find the following products and verify the result for x=-1,y=-2:(3x-5y)(x+y)(2)(x^(2)y-1)(3-2x^(2)y)((1)/(3)x-(y^(2))/(5))((1)/(3)x+(y^(2))/(5))

3x-y=2,5x-2y=1

If ((2x-y)/(x+2y))=(1)/(2), then find the value of ((3x-y)/(3x+y))

(a) 2x+y=5 ; 3x+2y=8