tan theta+tan(theta+(pi)/(3))+tan(theta+(2 pi)/(3))

The period of tan theta+ tan (theta+(pi)/(3)) +tan (theta+(2pi)/(3)) is

tan theta+tan(theta+(pi)/(3))+tan(theta-(pi)/(3))=k tan36 then k is equal to

sqrt(3)tantheta tan(theta + pi/3) tan(theta + (2pi)/3) =1

Solve the equations: tan theta + tan (theta + (pi)/(3)) + tan (theta + (2pi)/(3)) = sqrt(3)

If tan theta + tan ( theta + (pi)/(3))+ tan ( theta + (2pi)/(3))=3 , then which of the following is equal to 1 ?

If tan theta + tan ( theta + (pi)/(3))+ tan ( theta + (2pi)/(3))=3 , then which of the following is equal to 1 ?