f(x)=[[++sin k_(1)pi x,x" is rational "],[1+cos k_(2)pi x,x" is irrational "]|f(x)" is a periodicfunction,then "

f(x)=1 for x is rational -1 for x is irrational,f is continuous on

If f(x) = 2x + 3, then x is rational. =x^(2)+1 , when x is irrational. then find - (a) f(0), (b) f(pi) .

If f(x) = {{:((k cos x)/(pi - 2x), x ne pi//2),(1, x = pi//2):} , is a continous function at x = pi//2 , then the value of k is-

Two functions f:RtoR and g:RtoR are defined as follows: f(x)={(0,(x"rational")),(1,(x "irrational")):} g(x)={(-1,(x"rational")),(0,(x "irrational")):} then (gof)( e )+(fog) ( pi ) =

Two functions f:RtoR and g:RtoR are defined as follows: f(x)={(0,(x"rational")),(1,(x "irrational")):} g(x)={(-1,(x"rational")),(0,(x "irrational")):} then (gof)( e )+(fog) ( pi ) =

The function f(x) = (1-sin x + cos x)/(1+sin x + cosx) is not defined at x = pi . The value of f(pi) , so that f(x) is continuous at x = pi is

The function f(x) = (1-sin x + cos x)/(1+sin x + cosx) is not defined at x = pi . The value of f(pi) , so that f(x) is continuous at x = pi is

f(x)= sin^(2)x + sin^(2) (x + (pi)/(3)) + cos x cos (x + (pi)/(3)) then f'(x) = ………