4m-2n=-4;4m+3n=16

Solve the simultaneous equations using Cramer's rule 4m+6n=54, 3m+2n=28

4m-2n=2,6m-5n=9 then n=…………

4m+6n=54,3m+2n=28 .

If (4m + 3n)/(4m - 3n) = (7)/(4) use properties of proportion to find : (i) m : n (ii) (2m^(2) - 11n^(2))/(2m^(2) + 11n^(2)) .

Show that : (3x+7)^2-84 x=(3x-7)^2 (9a-5b)^2+180 a b=(9a+5b)^2 ((4m)/3-(3n)/4)^2+2m n=(16 m^2)/9+(9n^2)/(16)

If m and n satisfy the equations, 3m - n = 40 and4m - 2n = 50, then m=….

If tan theta+sin theta=m and tan theta-sin theta=n , then (a) m^2-n^2=4m n (b) m^2+n^2=4m n (c) m^2-n^2=m^2+n^2 (d) m^2-n^2=4sqrt(m n)

If tan theta+sin theta=m and tan theta-sin theta=n , then m^2-n^2is .... (a)4m n (b) m^2+n^2=4m n (c)m^2-n^2=m^2+n^2 (d) m^2-n^2=4sqrt(m n)

4m+3n=18.3m-2n=5

Show that ((4m)/3-(3n)/4)^2 +2mn = 16/9m^2+9/16 n^2