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If Q = (X^n)/(Y^m) and Delta X is abso...

If ` Q = (X^n)/(Y^m)` and `Delta X ` is absolute error in the measurement of X, `Delta Y` is absolute error in the measurement of Y, then absolute error `Delta Q ` in Q is :

Text Solution

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`Delta Q = (n (Delta X )/(X) + m (Delta Y)/(Y) ) Q`
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Knowledge Check

  • If Q=(x^n)/(y^m) and Deltax, Deltay are absolute errors in the measurement of x and y then absolute error DeltaQ in Q is

    A
    `DeltaQ =pm (n(Deltax)/x+m(Deltay)/y)`
    B
    `DeltaQ=pm(n(Deltax)/x+m(Deltay)/y)Q`
    C
    `DeltaQ=pm(n(Deltax)/x-m(Deltay)/y)Q`
    D
    `DeltaQ=pm(n(Deltax)/y-m(Deltay)/x)Q`

  • If Y = a//b , the maximum percentage error in the measurement of Y will be

    A
    `((Delta a)/(a) xx 100)//((Delta b)/(b) xx 100)`
    B
    `((Delta a)/(a) + (Delta b)/(b)) xx 100`
    C
    `((Delta a)/(a) xx 100)xx((Delta b)/(b) xx 100)`
    D
    `((Delta a)/(a) - (Delta b)/(b)) xx 100`

  • If Y = a x b , the maximum percentage error in the measurement of Y will be

    A
    `((Delta a)/(a) xx 100)//((Delta b)/(b) xx 100)`
    B
    `((Delta a)/(a) + (Delta b)/(b)) xx 100`
    C
    `((Delta a)/(a) xx 100)xx((Delta b)/(b) xx 100)`
    D
    `((Delta a)/(a) - (Delta b)/(b)) xx 100`

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    How is random error eliminated? What do you mean by absolute error?

    If Y=a/b ,the maximum percentage error in the measurement of Y will be

    What do you understand by absolute error ?

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