Force acting on a particle varies with x as shown in figure. Calculate the work done by the force as the particle moves from x = 0 to x = 6.0 m.

Explanation

The work done by the force is equal to the area under the curve from x = 0 to x = 6.0 m
This area is equal to the area of the rectangular section from x = 0 to x = 4.0 m plus the area of the triangular section from x = 4.0 m to x = 6.0 m. The area of the rectangle is (4.0) (5.0)
N.m = 20 J, and the area of the triangle is `(1)/(2)` (2.0),
(5,0) N.m = 5.0 J . Therefore, the total work done is 25 J .