A `1-KW` motor pumps out water from a well `10m` deep. Calculate the quantity of water pumped out per second.

Explanation

Power, P = 1 kilowatt = `10^(3)` watt
S = 10 m , Time, t = 1 second , mass of water, m = ?
Power = `(mg xx S )/(t)`
`therefore " " 10^(5) = (m xx 9.8 xx 10)/( 1 )`
or `" " m = (10^(3))/(9.8 xx 10)` kg = 10.204 kg