One coolie takes 1min to raise a box through a height of `2m`. Another one takes `30s` for the same job and does the same amount of work. Which one of the two has greater power and which one uses greater enegy?

Explanation

Power of first coolie = `("Work")/("time") = (M xx g xx S)/(t) `
`= (M xx 9.8 xx 2 )/(60) J s^(-1)`
Power of second coolie = `(M xx 9.8 xx 2 )/(30) J s^(-1) = 2 `
`((M xx 9.8 xx 2)/(60)) J s^(-1) = 2 xx` Power of first coolie
So, the power of the second coolie is double that of the first . Both the coolies spend the same amount of energy.
we know that W = Pt
for the same work ,
W = `rho_(1) t_(1) = P_(2) t_(2)`
or `" " (P_(2))/(P_(1)) = (t_(1))/(t_(2)) = (1 "minute" )/( 30 s ) = 2 `
or `" " P_(2) = 2P_(1) `