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A tansmitting antenna at the top of a tower has a height 32 m and that of the receiving antenna is 50 m. What is the maximum distance between them for satisfactory communication in line of sight mode ? Given radius of earth is `6.4 xx 10^(6) m`.

Text Solution

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`d=sqrt(2Rh_(T))+sqrt(2Rh_(R))`
`d=sqrt(2xx6.4xx10^(6)xx32)+sqrt(2xx6.4xx10^(6)xx50)`
`=64xx10^(2)xxsqrt10+8xx10^(3)xxsqrt10m`
= `144xx10^(2)xxsqrt10m=45.5km`
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