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Fraction of total power carried by side ...

Fraction of total power carried by side bands is given by-

A

`P_(s)/P_(T)=m^(2)`

B

`P_(s)/P_(T)=1/m^(2)`

C

`P_(s)/P_(T)=(2+m^(2))/m^(2)`

D

`P_(s)/P_(T)=m^(2)/(2+m^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
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