Prove that if p=2-a , then a^3+6ap+p^3-8...

Prove that if `p=2-a` , then `a^3+6ap+p^3-8=0`

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P=a
`a^3+6ap+p^3-8=0`
LHS
`a^3+6ap+p^3-8`
`a^3+6a(2-a)+(2-a)^3-8`
`a^3+6a*2-a)+8-a^3-6a(2-a)-8`
` `0`
RHS.

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