A line is a drawn from `P(4,3)` to meet the lines `L_1 and l_2` given by `3x+4y+5=0 and 3x+4y+15=0` at points `A and B` respectively. From `A` , a line perpendicular to `L` is drawn meeting the line `L_2` at `A_1` Similarly, from point `B_1` Thus a parallelogram `AA_1 B B_1` is formed. Then the equation of `L` so that the area of the parallelogram `AA_1 B B_1` is the least is (a) `x-7y+17=0` (b) `7x+y+31=0` (c) `x-7y-17=0` (d) `x+7y-31=0`

A line L is a drawn from P(4,3) to meet the lines L-1a n dL_2 given by 3x+4y+5=0 and 3x+4y+15=0 at points Aa n dB , respectively. From A , a line perpendicular to L is drawn meeting the line L_2 at A_1dot Similarly, from point B_1dot Thus, a parallelogram AA_1B B_1 is formed. Then the equation of L so that the area of the parallelogram AA_1B B_1 is the least is x-7y+17=0 7x+y+31=0 x-7y-17=0 x+7y-31=0

A line L is a drawn from P(4,3) to meet the lines L_1a n dL_2 given by 3x+4y+5=0 and 3x+4y+15=0 at points A and B , respectively. From A , a line perpendicular to L is drawn meeting the line L_2 at A_1 Similarly, from point B ,a line perpendicular to L is drawn meeting the line L_1 at B_1 Thus, a parallelogram A A_1B B_1 is formed. Then the equation of L so that the area of the parallelogram A A_1B B_1 is formed. Then the equation of L so that the area of the parallelogram AA 1 ​ BB 1 ​ is least is

A variable line L si drawn through O(0,0) to meet lines L_1 and L_2 " given by " y-x-10=0 and y-x-20=0 at point A and B, respectively. Locus of P, if OP^2=OAxxOB , is

A variable line L is drawn through O(0,0) to meet the line L_(1) " and " L_(2) given by y-x-10 =0 and y-x-20=0 at Points A and B, respectively. Locus of P, if OP^(2) = OA xx OB , is

A variable line L si drawn through O(0,0) to meet lines L_1 and L_2 " given by " y-x-10=0 and y-x-20=0 at point A and B, respectively. Locus of P if (1//OP^2)=(1//OA^2) , is

A variable line L si drawn through O(0,0) to meet lines L_1 and L_2 " given by " y-x-10=0 and y-x-20=0 at point A and B, respectively. A point P IS taken on L such that 2//OP=1//OA+1//OB . Then the locus of P is

A variable line L drawn through O(0,0) to meet line l1: y-x-10=0 and L2:y-x-20=0 at the point A and B respectively then locus of point p is ' such that (OP)^(2) = OA . OB,