[" 42."E^(0)Zn^(2+)/Zn=-0.76V" The EMF of the cell "Zn/],[Zn_((M))^(2+)|HCl(pH=2)|H_(2(latm)),Pt" is "],[[" 1) "0.878V," 2) "0.642V3)-0.878V," 4) "0.701V]]

E_(Zn^(2+)//Zn)^(0)=-0.76V The EMF of the cell Zn//Zn_((1M))^(2+)"||"HCl(pH=2)|H_2(1 atm)"),Pt is

For Zn^(2+)|Zn, E^(@)=-0.76V then EMF of the cell Zn|Zn^(2+)(1M)||2H^(+)(1M)|H_(2)(1atm) will be -

E^@ for the half cell Zn^(2+)|Zn is -0.76V emf of the cell Zn|Zn^(2+) (1M) |2H^+ (1M) |H_2 (1atm) is

E^(0) for the half cell Zn^(2+) // Zn is - 0.76 V . Emf of the cell Zn// Zn^(2+)(1M) // //H^(+)(1M) // H_2 at 1 atm is

E_(Cu^(2+)|Cu)^@ = +0.337 V, E_(Zn^(2+)| Zn)^@ = - 0.762 V. The EMF of the cell , Zn|Zn^(2+) (0.01M)||Cu^(2+) (0.01M)|Cu is

At 25^(@)C tempertaure, E_("cell")^ of the galvanic cell Zn|Zn^(2+)(aq, 1M)||H^(+)(aq)|H_(2)("g, 1 atm")|Pt is +0.583V . If E_(Zn^(2+)|Zn)^(@)=-0.76V , then pH of the aqueous solution present in the reduction half - cell is -

If E^@(Zn//Zn^(2+))=+0.76V , E^@ (Ag^+//Ag) =+0.80V , find the emf of the cell - Zn//Zn^(2+) (0.01M)abs"Ag+(0.1M)//Ag .

What is the EMF of the cell? Zn(s)|Zn^(2+)+(0.1M)||Sn^(2+)+(0.001M)||Sn(s) . Given E^(@)Zn^(2+)//Zn=0.76V,E_(Sn^(@2+)//Sn=-0.14V