(1)/(sin(x-a)sin(x-b))

If int(k)/(sin(x-a)sin(x-b))dx=log[(sin(x-a))/(sin(x-b))]+c, then k=

int (dx)/(sin(x-a)sin(x-b)) is

int (dx)/(sin(x-a)sin(x-b)

int (dx)/(sin (x-a) sin (x-b)) is :

int dx/(sin(x-a)sin(x-b)) =

int(dx)/(sin(x+a)sin(x+b))=

int (sin (x-a))/(sin (x-b))dx=

int frac{1}{sin(x-a) sin(x-b)} dx =.......... A) int frac{1}{sin(b-a)} log frac{sin(x-b)}{sin(x-a)} + c B) int frac{1}{sin(a-b)} log| frac{sin(x-a)}{sin(x-b)} | + c C) int frac{1}{cos(a-b)} log| frac{sin(x-b)}{sin(x-a)} | + c D) int frac{1}{cos(a-b)} log| frac{sin(x-a)}{sin(x-b)} | + c