(vi)(sec(90^(@)-theta)cosec theta-tan(90^(@)-theta)cot theta+cos^(2)25^(@)+cos^(2)65^(@))/(3tan27^(@)tan63^(@))=(2)/(3)

Without using trigonometric tables,find the value of the following expression: (sec(90-theta)*cos ec theta tan(90-theta)cot theta+cos^(2)25+cos^(2)65)/(3tan27^(@)*tan63^(@))

Without using trigonometric tables, find the value of the following expression : (sec (90°-theta).cosec theta — tan (90°-theta) cot theta + cos^2 25° + cos^2 65°)/(3tan27^@.tan63^@)

(tan(90^@-theta) cot theta)/(cosec^2 theta)-cos^2 theta=0

Without using trigonometric table, the value of cotthetatan(90^(@)-theta)-sec(90^(@)-theta)"cosec"theta+sin^(2)65^(@)+sin^(2)25^(@)+sqrt3tan5^(@)tan85^(@) .

The value of cottheta.tan(90^(@)-theta)-sec(90^(@)-theta)cosectheta+(sin^(2)25^(@)+sin^(2)65^(@)) is

tan^(2)(90^(@) - theta) - cosec^(2) theta =

tan^(2)(90^(@) - theta) - cosec^(2) theta =

(sec theta+csc theta)^(2)-(tan theta+cot theta)^(2)=

Prove that :(sin theta cos(90^(0)-theta)cos theta)/(sin(90^(0)-theta))+(cos theta sin(90^(0)-theta)sin theta)/(cos(90^(@)-theta))=1csc^(2)(90^(@)-theta)-tan^(2)theta=cos^(2)(90^(@)-theta)+cos^(2)theta