`CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(3)overset(Cl_(2))underset(h_(v))(to)` Number of monochloro product including stereoisomers.
A
`4`
B
`5`
C
`6`
D
`7`
Text Solution
Verified by Experts
The correct Answer is:
c
Products are `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)-Cl` `:.` 6-Products
Topper's Solved these Questions
HYDROCARBONS (ALKANES)
MS CHOUHAN|Exercise Level 1 (Q.1 To Q.30)|1 Videos
HYDROCARBONS (ALKANES)
MS CHOUHAN|Exercise Level 1 (Q.31 To Q.50)|1 Videos
ALKYL HALIDES
MS CHOUHAN|Exercise Level -2|1 Videos
HYDROCARBONS (ALKENES)
MS CHOUHAN|Exercise LEVEL - 2|1 Videos
Similar Questions
Explore conceptually related problems
CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(3)overset(Cl_(2))underset(h_(v))(to) Number of chiral generated during monochlorination in the above reaction:
CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)-CH_(3)underset(hv)overset(Cl_(2))rarr Mono-chloro product (inculding steroisomers) are :
CH_(3)-overset(CH_(3))overset(|)CH-CH_(2)-CH_(3) overset(Cl_(2))underset("UV light")to underset("major")((A)) , The compound "A" is
Ph-underset(CH_(3))underset(|)(C )H-CH_(2)-CH_(3)overset(Cl_(2))underset(hv)rarr"Products" overset("Fractional")underset("Distillation")rarr "Fractions" , No of products and no of fractions are respectively:
CH_(3)-underset(CH_(3))underset(|)(C)=CH-CH_(2)-underset(O)underset(||)(C)-CH_(3)overset(H_(2)//Pd//C)rarr Number of stereoisomers formed in the given reaction is
CH_(3)-underset(CH_(3))underset(|)(CH)-underset(H)underset(|)overset(Cl)overset(|)(C)-CH_(3)overset(CH_(3)OH)to major product is
MS CHOUHAN-HYDROCARBONS (ALKANES)-Level 1 (Q.31 To Q.50)