Calcium carbide + heavy water `rarr` ? The product of the above reaction is :
A
`C_(2)H_(2)`
B
`CaD_(2)`
C
`Ca(OD)_(2)`
D
`CD_(4)`
Text Solution
Verified by Experts
The correct Answer is:
c
`CaC_(2)+D_(2)OtoCa(OD)_(2)+D-C-=C-D`
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