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Bromination of (E)-2-butenedioic acid gi...

Bromination of (E)-2-butenedioic acid gives

A

(2R, 3S)-2, 3-dibromosuccinic acid

B

(2R, 3R)-2, 3-dibromosuccinic acid

C

a mixture of (2R, 3R) and (2S, 3S)-2,3-dibromosuccinic acid

D

(2S, 3S)-2,3-dibromosuccinic acid

Text Solution

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The correct Answer is:
To solve the problem of what product is formed from the bromination of (E)-2-butenedioic acid, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Structure of (E)-2-butenedioic acid**: - The structure of (E)-2-butenedioic acid (also known as fumaric acid) can be represented as: \[ \text{HOOC-CH=CH-COOH} \] - In this structure, the two carboxylic acid groups (COOH) are on opposite sides of the double bond, which is characteristic of the E configuration. 2. **Understand the Bromination Reaction**: - Bromination involves the addition of bromine (Br2) across the double bond. The reaction can be represented as: \[ \text{C=C} + \text{Br}_2 \rightarrow \text{Br-CH-CH-Br} \] - This reaction proceeds through a cyclic bromonium ion intermediate. 3. **Mechanism of Bromination**: - The Br2 molecule dissociates into Br+ and Br−. The Br+ attacks one of the carbons of the double bond, forming a bromonium ion. - The Br− then attacks the more substituted carbon from the opposite side (backside attack), leading to anti-addition. 4. **Draw the Product**: - After the bromination, the product will have bromine atoms added to the two carbons of the double bond. The resulting structure will be: \[ \text{HOOC-CH(Br)-C(Br)-COOH} \] - This product is known as 2,3-dibromosuccinic acid. 5. **Determine the Configuration**: - The product will have two stereocenters at the carbons where bromine is added. The configurations can be determined by assigning priorities based on the Cahn-Ingold-Prelog rules. - The resulting product will have one stereocenter with R configuration and the other with S configuration, leading to the final product being 2R, 3S-2,3-dibromosuccinic acid. ### Final Answer: The product of the bromination of (E)-2-butenedioic acid is **2R, 3S-2,3-dibromosuccinic acid**. ---

To solve the problem of what product is formed from the bromination of (E)-2-butenedioic acid, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Structure of (E)-2-butenedioic acid**: - The structure of (E)-2-butenedioic acid (also known as fumaric acid) can be represented as: \[ \text{HOOC-CH=CH-COOH} ...
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