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H(2)overset(14)(C)=CH-CH(3)overset("low ...

`H_(2)overset(14)(C)=CH-CH_(3)overset("low conc. of "Br_(2))underset("or high temp")(to)(?)`
Product of the above reaction is:

A

`H_(2)overset(14)(C)=CH-CH_(3)-Br`

B

`H_(2)C=CH-overset(14)(CH_(2))-Br`

C

`overset(14)underset(Br)underset(|)(C)H_(2)-underset(Br)underset(|)(C)H-CH_(3)`

D

Both (a) and (b)

Text Solution

Verified by Experts

The correct Answer is:
d
Low conc. Of `Br_(2)` and high temperature favour substitution reaction, proceed through free radical.
`therefore` Substitutaion will be major product.
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