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CH(3)-overset(CH(3))overset(|)(CH)-C-=CH...

`CH_(3)-overset(CH_(3))overset(|)(CH)-C-=CH overset("excess HBr")(to)`
The product of the above reaction is:

A

`CH_(3)-overset(CH_(3))overset(|)(CH)-overset(Br)overset(|)(CH)-overset(Br)overset(|)(CH_(2))`

B

`CH_(3)-overset(CH_(3))overset(|)(CH)-overset(Br)overset(|)(C)=CH_(2)`

C

`CH_(3)-overset(CH_(3))overset(|)(CH)-overset(Br)overset(|)underset(Br)underset(|)(C)-CH_(3)`

D

`CH_(3)-overset(CH_(3))overset(|)(CH)-CH_(2)-overset(Br)overset(|)underset(Br)underset(|)(CH)`

Text Solution

Verified by Experts

The correct Answer is:
C
`CH_3-overset(CH_(3))overset(|)CH-C-=CHoverset(H^(+)Br^(-))toCH_(3)-overset(CH_(3))overset(|)CH-underset(Br)underset(|)C=CH_(2)overset(H^(+)Br^(-))toCH_(3)-overset(CH_(3))overset(|)CH-overset(Br)overset(|)underset(Br)underset(|)C-CH_(3)`
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