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[int(x)-(5)/(x-1),+(1)/(y-2)=2],[(6)/(x-...

[int(x)-(5)/(x-1),+(1)/(y-2)=2],[(6)/(x-1),-(3)/(x-2)=1]

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solve for x and y . (5)/(x-1)+(1)/(y-2) =2 and ( 6) / ( x-1) -(3)/ (y-2) =1

If (5)/(x-1)+(1)/(y-2)=2,(6)/(x-1)+(-3)/(y-2)=1 then x=……….

{:((5)/(x - 1) + (1)/(y - 2) = 2),((6)/(x - 1) - (3)/(y - 2) = 1):}

(5) / (x-1) + (1) / (y-2) = 2 (6) / (x-1) - (3) / (y-2) = 1

Solve for x and y. 5/(x-1)+1/(y-2)=2" and "6/(x-1)-3/(y-2)=1

Solve for x and y 5/(x-1)+1/(y-2)=2" and "6/(x-1)-3/(y-2)=1

Solve for x and y : (6)/(x-1)-(3)/(y-2)=1 (5)/(x-1)-(1)/(y-2)=2 , where x ne 1, y ne 2 .

5/(x-1)+1/(y-2)=2 and 6/(x-1)-3/(y-2)=1 then find the values of x and y

Add :5x^(2)-(1)/(3)x+(5)/(2),-(1)/(2)x^(2)+(1)/(2)x-(1)/(3) and -2x^(2)+(1)/(5)x-(1)/(6)