I=int_(0)^(12)(mu log n)/(sec x+tan x)

log (sec 2x +tan 2 x)

int_(0)^(pi)(x tanx)/(sec x +tan x)dx

int_(0)^(pi//2)log (sec x) dx=

int_(0)^(pi//2) sec x log (sec x+tan x) dx is equal to

int_(0)^(pi//4) sec x log (sec x+tan x) dx is equal to

Evaluate of each of the following integrals (1- 15): int_(0)^(2 pi)log(sec x+tan x)dx

If g (x) = int_(0)^(x) ln(sec t tan t - sec^(2)t + 1) dt , then set of value of x in ((-pi)/(2) , (pi)/(2)) for which g(x) is increasing , is

If int_(0)^(pi//2) log(cosx) dx=pi/2 log (1/2), then int_(0) ^(pi//2) log (sec x ) dx =

(d)/(dx)[log(sec x+tan x)]=

int (sec x dx)/(log (sec x +tan x)) =