For an A.P `S_(100)=3S_(50)` then `S_150:S_50`

S_(n) denote the sum of the first n terms of an A.P. If S_(2n)=3S_(n) , then S_(3n):S_(n) is equal to

If in an A.P., S_(2n)=3.S_(n) then S_(3n) : S _(n) = (a)5 (b) 6 (c)7 (d)8

Let S_(n) denote the sum of the first n terms of an A.P. If S_(2n) = 3S_(n) , then S_(3n) : S_(n) is equal to :

For an A.P., if S_(10) =150 and S_(9) = 125 , find t_(10)

If S_(n) denotes the sum of first n terms of an A.P. and S_(2n)= 3S_(n) , then (S_(3n))/(S_(n))=

S_(n) is the sum of n terms of an A.P. If S_(2n)= 3S_(n) then prove that (S_(3n))/(S_(n))= 6

Let S_(1), S_(2), ...... S_(101) be consecutive terms of A.P. If 1/(S_(1)S_(2)) + 1/(S_(2)S_(3)) + ...... + 1/(S_(100)S_(101)) = 1/6 and S_(1) + S_(101) = 50 , then |S_(1) - S_(101)| is equal to

For an A.P. if S_10=150 and S_9=126 , find t_10 .

For an A.P., S_(1)=6 and S_(7)= 105 . Prove that S_(n): S_(n-3) = (n+ 3): (n-3)

If S_n denotes the sum of the first n terms of an A.P., prove that S_(30)=3(S_(20)-S_(10)) .