If `f'(x)=x^2+5` and `f(0)=-1` then `f(x)=`

If f'(x)=f(x) and f(0)=1 then lim_(x rarr0)(f(x)-1)/(x)=

f(x) is a continuous and differentiable function. f'(x) ne 0 and |{:(f'(x),f(x)),(f''(x),f'(x)):}|=0 . If f(0)=1 and f'(0)=2 then f(x)=....

If f(x)=x^(2)+3x-5, find f(0),f(1) and f((1)/(2))

If f'(2)=6 and f'(1)=4 ,then lim_(x rarr0)(f(x^(2)+2x+2)-f(2))/(f(1+x-x^(2))-f(1)) is equal to ?

Let f(x) be a polynomial function: f(x)=x^(5)+ . . . . if f(1)=0 and f(2)=0, then f(x) is divisible by

Suppose |[f'(x),f(x)],[f''(x),f'(x)]|=0 is continuously differentiable function with f^(prime)(x)!=0 and satisfies f(0)=1 and f'(0)=2 then lim_(x->0)(f(x)-1)/x is a. 1//2 b. 1 c. 2 d. 0

If Delta=det[[f(x),f((1)/(x))+f(x)1,f((1)/(x))]]=0 where it is given f(x)=a+bx^(n) and f(2)=17 and f(5)=K then K-620=

If f(x) = 2x - 5, then f (0) is :

If f(x) = x^2-5|x|+2 , find f(0),f(1),f(-1)