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An oxide of iron contains 69.94% Fe and ...

An oxide of iron contains `69.94% Fe` and `30.06%O`. Determine its E.F. `(Fe = 55.85, O = 16.0)`

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`{:("Element",Fe,O),(%"composition",=69.94,30.06),("Mole ratio",(69.94)/(55.85)=1.25,(30.06)/(16)=1.88),("simple mole ratio",(1.25)/(1.25)=1xx2,(1.88)/(1.25)=1.5 xx 2 = 3),("whole number ratio",2,3):}`
`E.F = Fe_(2)O_(3)`
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