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On analysis of a compund, it was found t...

On analysis of a compund, it was found that it contains (i) 4.08 grams Na (ii) 0.264 mole oxygen atoms (ii) `5.3 xx 10^(22)` atoms of carbon. Determine its E.F.

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Determine the mole ratio
`Na : C : O = (4.08)/(23) : (5.3 xx 10^(22))/(6.23 xx 10^(23)) : 0.264`
or Simple mole ratio `= 2:1:3` or `E.F. = Na_(2)CO_(3)`
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