What volume of carbon monoxide at 2 atm and `273^(@)C` is required in order to produce 5.6 grams of metal by the reduction of ferric oxide ?

Explanation

Reduction of ferric oxide with carbonmonoxide gives irom metal.
`Fe_(2)O_(3) +3CO rarr 3CO_(2) +2Fe`
56 gram of `Fe = 33.6 L` of `CO` at STP
5.6 grams of `Fe = 3.36` lit of Co at STP
`{:(STP "conditions","Given conditions"),(P_(1)=1atm,P_(@)=2atm),(T_(1)=273K,T_(2)=2'273K),(V_(1)=3.36L,V_(2)=?):}`
`V_(2) = (P_(1)V_(1))/(T_(1)) xx (T_(2))/(P_(2)) = (1 xx 3.36 xx 2 xx 273)/(273 xx 2) = 3.36 L`