The volume of `O_(2)` at S.T.P required for completely burnt out 100 ml. of ethane is

Explanation

`C_(2)H_(6) +(7)/(2)O_(2) rarr 2CO_(2)+3H_(2)O`
1ml. Of ethane require `7//2` ml. of oxygen
Volume of `O_(2)` required to burn 100 ml of `C_(2)H_(6) = (100)/(1) xx (7)/(2) = 350 ml`