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The volume of CO(2) liberated at S.T.P a...

The volume of `CO_(2)` liberated at S.T.P and the quantity of heat energy liberated from the combustion of 2.3 g of ethyl alcohol are
`C_(2)H_(5)OH(l) +3O_(2)(g) rarr`
`2CO_(2)(g)+3H_(2)O(l) +1367.2`

Text Solution

Verified by Experts

Molecular weight of `C_(2)H_(5)OH = 46`
46 grams of `C_(2)H_(5)OH` on combustion liberate `2 xx 22.4` lit of `CO_(2)` at S.T.P. and 1367.2 of energy. Volume of `CO_(2)` liberated by the combustion of 2.3 g. of `C_(2)H_(5)OH`
`(2.3)/(46) xx 2 xx 22.4 = 2.24` lit
Energy liberated by the combustion of 2.3 g
`C_(2)H_(5)OH = (2.3)/(46) xx 1367.2 = 68.36 k.j`
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