Atomicity of oleum `(H_(2)S_(2)O_(7))` is

Options

A. 11
B. 8
C. 7
D. 18

Explanation

To determine the atomicity of oleum (H₂S₂O₇), we need to find the total number of atoms present in one molecule of the compound.

### Step-by-Step Solution:

1. **Identify the elements in the compound**:
The formula for oleum is H₂S₂O₇. This indicates that the compound contains:
- Hydrogen (H)
- Sulfur (S)
- Oxygen (O)

2. **Count the number of atoms of each element**:
- From the formula H₂S₂O₇:
- There are 2 hydrogen atoms (H).
- There are 2 sulfur atoms (S).
- There are 7 oxygen atoms (O).

3. **Calculate the total number of atoms**:
To find the atomicity, we add the number of atoms of each element together:
\[ \text{Total atoms} = \text{Number of H atoms} + \text{Number of S atoms} + \text{Number of O atoms} \]
\[ \text{Total atoms} = 2 + 2 + 7 \]
\[ \text{Total atoms} = 11 \]

4. **Conclusion**:
The atomicity of oleum (H₂S₂O₇) is 11.

### Final Answer:
The atomicity of oleum (H₂S₂O₇) is **11**.

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