For which of the following salt, Eq.wt is F.W/6

Options

A. `NaCI`
B. `K_(2)SO_(4)`
C. `Fe_(2)(SO_(4))_(3)`
D. `AlCl_(3)`

Explanation

To determine which salt has an equivalent weight equal to its formula weight divided by 6, we need to find the n-factor (number of moles of reactive species produced or consumed in a reaction) for each salt. The equivalent weight (Eq.wt) is calculated using the formula:

\[ \text{Eq.wt} = \frac{\text{F.W}}{n} \]

Where F.W is the formula weight (or molar mass) and n is the n-factor. We are looking for a salt where n = 6.

### Step-by-Step Solution:

1. **Identify the salts given in the question**:
- NaCl
- K₂SO₄
- Fe₂(SO₄)₃
- AlCl₃

2. **Calculate the n-factor for each salt**:
- **NaCl**:
- Dissociates into Na⁺ and Cl⁻.
- n-factor = 1 (1 electron transferred).

- **K₂SO₄**:
- Dissociates into 2K⁺ and SO₄²⁻.
- n-factor = 2 (2 electrons transferred).

- **Fe₂(SO₄)₃**:
- Dissociates into 2Fe³⁺ and 3SO₄²⁻.
- Each Fe³⁺ contributes +3, thus total charge = 2 × 3 = 6.
- n-factor = 6 (6 electrons transferred).

- **AlCl₃**:
- Dissociates into Al³⁺ and 3Cl⁻.
- n-factor = 3 (3 electrons transferred).

3. **Compare the n-factors**:
- NaCl: n = 1
- K₂SO₄: n = 2
- Fe₂(SO₄)₃: n = 6
- AlCl₃: n = 3

4. **Identify the salt with n-factor equal to 6**:
- The only salt with an n-factor of 6 is **Fe₂(SO₄)₃**.

5. **Conclusion**:
- Therefore, the salt for which the equivalent weight is equal to the formula weight divided by 6 is **Fe₂(SO₄)₃**.

### Final Answer:
The salt for which Eq.wt = F.W/6 is **Fe₂(SO₄)₃**.