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Na(2)SO(3)+H(2)O(2) rarr Na(2)SO(4) +H(2...

`Na_(2)SO_(3)+H_(2)O_(2) rarr Na_(2)SO_(4) +H_(2)O`, in reaction

A

`H_(2)O_(2)` is bleached

B

`H_(2)O_(2)` is reduced

C

`H_(2)O_(2)` is dehydrated

D

`H_(2)O_(2)` is neither oxidised nor reduced

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To solve the reaction \( \text{Na}_2\text{SO}_3 + \text{H}_2\text{O}_2 \rightarrow \text{Na}_2\text{SO}_4 + \text{H}_2\text{O} \), we will follow these steps: ### Step 1: Identify the Reactants and Products The reactants in this reaction are sodium sulfite (\( \text{Na}_2\text{SO}_3 \)) and hydrogen peroxide (\( \text{H}_2\text{O}_2 \)). The products are sodium sulfate (\( \text{Na}_2\text{SO}_4 \)) and water (\( \text{H}_2\text{O} \)). ### Step 2: Write the Balanced Equation The unbalanced equation is: \[ \text{Na}_2\text{SO}_3 + \text{H}_2\text{O}_2 \rightarrow \text{Na}_2\text{SO}_4 + \text{H}_2\text{O} \] To balance the equation, we need to ensure that the number of each type of atom is the same on both sides. ### Step 3: Balance the Sodium (Na) Atoms In the reactants, there are 2 sodium atoms from \( \text{Na}_2\text{SO}_3 \) and in the products, there are also 2 sodium atoms from \( \text{Na}_2\text{SO}_4 \). The sodium atoms are balanced. ### Step 4: Balance the Sulfur (S) Atoms There is 1 sulfur atom in \( \text{Na}_2\text{SO}_3 \) and 1 sulfur atom in \( \text{Na}_2\text{SO}_4 \). The sulfur atoms are balanced. ### Step 5: Balance the Oxygen (O) Atoms In the reactants, we have: - 3 oxygen atoms from \( \text{Na}_2\text{SO}_3 \) - 2 oxygen atoms from \( \text{H}_2\text{O}_2 \) Total = \( 3 + 2 = 5 \) oxygen atoms. In the products, we have: - 4 oxygen atoms from \( \text{Na}_2\text{SO}_4 \) - 1 oxygen atom from \( \text{H}_2\text{O} \) Total = \( 4 + 1 = 5 \) oxygen atoms. The oxygen atoms are balanced. ### Step 6: Confirm the Balanced Equation The balanced equation is: \[ \text{Na}_2\text{SO}_3 + \text{H}_2\text{O}_2 \rightarrow \text{Na}_2\text{SO}_4 + \text{H}_2\text{O} \] ### Step 7: Conclusion The reaction shows that sodium sulfite is oxidized to sodium sulfate by hydrogen peroxide, which acts as an oxidizing agent. ---

To solve the reaction \( \text{Na}_2\text{SO}_3 + \text{H}_2\text{O}_2 \rightarrow \text{Na}_2\text{SO}_4 + \text{H}_2\text{O} \), we will follow these steps: ### Step 1: Identify the Reactants and Products The reactants in this reaction are sodium sulfite (\( \text{Na}_2\text{SO}_3 \)) and hydrogen peroxide (\( \text{H}_2\text{O}_2 \)). The products are sodium sulfate (\( \text{Na}_2\text{SO}_4 \)) and water (\( \text{H}_2\text{O} \)). ### Step 2: Write the Balanced Equation The unbalanced equation is: \[ ...
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NARAYNA-SOME BASIC CONCEPTS IN CHEMISTRY STOICHIOMETRY (PART-I)-All Questions
  1. The oxidation number of Oxygen in KO(2) is

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  2. The oxidation number and covalency of sulphur in the sulphur molecule ...

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  3. Na(2)SO(3)+H(2)O(2) rarr Na(2)SO(4) +H(2)O, in reaction

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  4. In which of the following compounds, sulphur atom has different oxida...

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  5. Change in oxidation number is maximum in the following reaction

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  6. Which of the following are neutral oxide?

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  7. The oxidation state of N in HNO(4) is

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  8. Which of the following can acts as a reducing agent ?

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  9. Which of the following is displacement reaction :

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  10. N kg^(-1) is the unit of :

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  11. Prefix zepto and femto stands for which multiples ?

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  12. The number of significant figures in N(0) = 6.022 xx 10^(23) (Avogadro...

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  13. The correctly reported answer of the addition of 4.523, 2.3 and 6.24 w...

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  14. The answer of the calculation (2.568 xx 5.8)/(4.168) in significant fi...

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  15. How many significant figures are present in the following ? (i) 0.00...

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  16. 314.000 has how many significant figures.

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  17. The correctly reported difference of 16.4215 and 6.01 will have signif...

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  18. After rounding off 1.235 and 1.225, we will have their answer respecti...

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  19. In the formation of SO(2) and SO(3) the ratio of the weights of oxygen...

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  20. 14gm of element X combine with 16gm of oxygen. On the basis of this in...

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