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The number of atoms in 4.25 g of NH(3) i...

The number of atoms in 4.25 g of `NH_(3)` is approximately

A

`1 xx 10^(23)`

B

`1.5 xx 10^(23)`

C

`2 xx 10^(23)`

D

`6 xx 10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(4.25)/(17) xx 4 = 1`
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