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The weight of KMnO(4) required to comple...

The weight of `KMnO_(4)` required to completely oxidise 0.25 moles of `FeSO_(4)` in acid medium is...........(molecular weight of `KMnO_(4) = 158`)

A

5.8

B

1.5

C

7.9

D

0.79

Text Solution

Verified by Experts

The correct Answer is:
C
`2KMnO_(4) +3H_(2)SO_(4) +10 FeSO_(4) rarr K_(2)SO_(4) +2MnSO_(4) +5Fe_(2)(SO_(4))_(3) +3H_(2)O`
`2 xx 158 gm` of `KMnO_(4)`
`rarr 10` moles of `FeSO_(4)`?
`-0.25` moles `FeSO_(4)`
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