Home
Class 11
CHEMISTRY
If 5.85 g of NaCl is dissolved in 90g of...

If 5.85 g of `NaCl` is dissolved in 90g of water, the mole fraction of solute is

A

`0.0196`

B

`0.01`

C

`0.1`

D

`0.2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the mole fraction of NaCl when 5.85 g of NaCl is dissolved in 90 g of water, we can follow these steps: ### Step 1: Calculate the number of moles of NaCl The formula for calculating the number of moles is: \[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \] - Given mass of NaCl = 5.85 g - Molar mass of NaCl = Atomic mass of Na (23 g/mol) + Atomic mass of Cl (35.5 g/mol) = 58.5 g/mol Now, we can calculate the number of moles of NaCl: \[ \text{Number of moles of NaCl} = \frac{5.85 \, \text{g}}{58.5 \, \text{g/mol}} = 0.1 \, \text{mol} \] ### Step 2: Calculate the number of moles of water Using the same formula: - Given mass of water = 90 g - Molar mass of water (H₂O) = 2 × Atomic mass of H (1 g/mol) + Atomic mass of O (16 g/mol) = 18 g/mol Now, we can calculate the number of moles of water: \[ \text{Number of moles of water} = \frac{90 \, \text{g}}{18 \, \text{g/mol}} = 5 \, \text{mol} \] ### Step 3: Calculate the mole fraction of NaCl The mole fraction of a solute is given by: \[ \text{Mole fraction of solute} = \frac{\text{Number of moles of solute}}{\text{Number of moles of solute} + \text{Number of moles of solvent}} \] Substituting the values we calculated: \[ \text{Mole fraction of NaCl} = \frac{0.1 \, \text{mol}}{0.1 \, \text{mol} + 5 \, \text{mol}} = \frac{0.1}{5.1} \] Calculating this gives: \[ \text{Mole fraction of NaCl} \approx 0.0196 \] ### Final Answer The mole fraction of NaCl is approximately **0.0196**. ---

To find the mole fraction of NaCl when 5.85 g of NaCl is dissolved in 90 g of water, we can follow these steps: ### Step 1: Calculate the number of moles of NaCl The formula for calculating the number of moles is: \[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLID STATE

    NARAYNA|Exercise LEVEL-V|122 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - IV|43 Videos

Similar Questions

Explore conceptually related problems

6g .of Urea is dissolved in 90g .of water.The mole fraction of solute is

If 1.8 g of glucose (molar mass = 180) is dissolved in 60 g of water the mole fraction of glucose is

Knowledge Check

  • If 5.85g of NaCl are dissolved in 90g of water, the mole fraction of solute is

    A
    0.0196
    B
    0.01
    C
    0.1
    D
    0.2
  • If 5.85 g of NaCl are dissolved in 90g of water,the moles fraction of NaCl is

    A
    `0.1`
    B
    `0.2`
    C
    `0.3`
    D
    `0.0196`
  • 5.85 g of NaCl are dissolved in 90 g of water. The mole fraction of NaCl is-

    A
    0.1
    B
    0.01
    C
    0.2
    D
    0.0196
  • Similar Questions

    Explore conceptually related problems

    If 5.85 gms of NaCl are dissolved in 90 gms of water,the mole fraction of NaCl is

    If 5.85 gms of NaCl are dissolved in 90 gms of water, the mole fraction of NaCl is

    2.82g of glucose is dissolved in 30g of water. The mole fraction of glucose in the solution is

    5.85 g NaCl is dissolved in 500 ml of water. The molarity is

    92 g. of ethanol is dissolved in 108g. Of water. The mole fraction of water in the solution is